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Bracket Talk Bracket Talk Forum Tech Talk - by Abruzzi Math ....does this look right?Go | New | Find | Notify | Tools | Reply | |
| Math ....does this look right? | Login/Join |
| DRR Sportsman |
Trying to figure out how far a car would travel in .004 second at 130mph. I somehow came up with 9.15 inches. Just wondering if that is correct or if it's not even close. | ||
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| DRR Pro |
^^^^^^ Correct !! | |||
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DRR Pro |
my math says same as yours,for certain not sure honesty is the best policy,insanity is a better deffense 1.036, 6.16@ 224 | |||
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| DRR Sportsman |
Thanks. That verifies that I can't drive for S@#&. | |||
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DRR S/Pro |
Last year I took the stripe by .0001@190mph, best we could figure it was about 5/16"...... 272" Spitzer 540 Chevy The Blower Shop XR1 FTI XPM Series Converter FTI Level 6 Powerglide 3.69@199 .916 60' 2017 Bradenton Heads Up Madness Open Outlaw Champ 2018 PDRA T/D #5 2019 PDRA T/D #2 2020 Retired From T/D Competition.... 2020 Bradenton NMCA Hemi Shootout Winner 2021 getting back into bracket racing with a Gen3 Hemi powered 87 Cutlass. | |||
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| DRR S/Pro |
Speed X 5280 divided by 3600 = distance per second Therefore 130 mph X 5280 divided by 3600 = 190.66666 ft. per second 19.666 ft. per .10 second 1.9 ft. per .01 seconds .19666 ft. per .001 Another (faster but not as exact) formula used is speed X 1.47 therefore 130 X 1.47 = 191.1000 Bob | |||
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DRR S/Pro |
Minor quibble but if you took the stripe, your MPH is irrelevant. The trailing car's MPH is what matters. Tony Leonard | |||
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| DRR S/Pro |
Ahh, didn't think of that. He was 184mph 272" Spitzer 540 Chevy The Blower Shop XR1 FTI XPM Series Converter FTI Level 6 Powerglide 3.69@199 .916 60' 2017 Bradenton Heads Up Madness Open Outlaw Champ 2018 PDRA T/D #5 2019 PDRA T/D #2 2020 Retired From T/D Competition.... 2020 Bradenton NMCA Hemi Shootout Winner 2021 getting back into bracket racing with a Gen3 Hemi powered 87 Cutlass. | |||
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| DRR S/Pro |
Only changes it .01". Makes it a little closer to your 5/16", which is pretty much the right fraction to use. Some good work! Tony Leonard | |||
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| DRR S/Pro |
Thanks, but my Wife is a teacher, I'll have to credit her with that one...… She did say it was a little over 5/16" Just call me stripe hog! 272" Spitzer 540 Chevy The Blower Shop XR1 FTI XPM Series Converter FTI Level 6 Powerglide 3.69@199 .916 60' 2017 Bradenton Heads Up Madness Open Outlaw Champ 2018 PDRA T/D #5 2019 PDRA T/D #2 2020 Retired From T/D Competition.... 2020 Bradenton NMCA Hemi Shootout Winner 2021 getting back into bracket racing with a Gen3 Hemi powered 87 Cutlass. | |||
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| DRR S/Pro |
Make it easier 17.6 x MPH x MOV in seconds Also the MPH that should be used is the car that crosses the finish line second, which is not necessarily your MPH! | |||
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| DRR Trophy |
I think it is 1.467 x mov X second cars mph! | |||
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| DRR S/Pro |
Same thing, just one is in feet and the other in inches! | |||
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DRR Trophy |
TOP 38 has it 100% correct....below is the long version of where the 17.6 comes from 5280/60/60*12=17.6 MOV*MPH*5280/60/60*12 got beat to finish line by .0051 1/4 mile speed of 2nd to finish line 175.966 .0051*175.966*5280/60/60*12 = 15.795 inches behind *5280 makes miles per hour feet per hour /60 makes feet per hour feet per minute /60 makes feet per minute feet per second *12 makes feet per second inches per second MOV is what part of a second you were behind slightly inacurate in that the trap speed is assumed to be the speed during the MOVThis message has been edited. Last edited by: fast5982, | |||
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Bracket Talk Bracket Talk Forum Tech Talk - by Abruzzi Math ....does this look right?
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